(3x+1)(2x^2+4x-3)=

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Solution for (3x+1)(2x^2+4x-3)= equation: 


Simplifying
(3x + 1)(2x2 + 4x + -3) = 0

Reorder the terms:
(1 + 3x)(2x2 + 4x + -3) = 0

Reorder the terms:
(1 + 3x)(-3 + 4x + 2x2) = 0

Multiply (1 + 3x) * (-3 + 4x + 2x2)
(1(-3 + 4x + 2x2) + 3x * (-3 + 4x + 2x2)) = 0
((-3 * 1 + 4x * 1 + 2x2 * 1) + 3x * (-3 + 4x + 2x2)) = 0
((-3 + 4x + 2x2) + 3x * (-3 + 4x + 2x2)) = 0
(-3 + 4x + 2x2 + (-3 * 3x + 4x * 3x + 2x2 * 3x)) = 0
(-3 + 4x + 2x2 + (-9x + 12x2 + 6x3)) = 0

Reorder the terms:
(-3 + 4x + -9x + 2x2 + 12x2 + 6x3) = 0

Combine like terms: 4x + -9x = -5x
(-3 + -5x + 2x2 + 12x2 + 6x3) = 0

Combine like terms: 2x2 + 12x2 = 14x2
(-3 + -5x + 14x2 + 6x3) = 0

Solving
-3 + -5x + 14x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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